Show Answer to the Exercise:

P = 12 cm, A = = 6.93 cm², α = β = γ = 60°, α' = β' = γ' = 120°

α = β = 43°30', γ = 93°

6 cm

45°

a = 3 dm, b = 4 dm, α = 36°52', β = 53°08'

b = = 11.66 cm, m_b = = 10.3 cm

a) h = 8.31 m
b) α = 77°46'

| MN | = 2(6 –) = 7.10 cm or | MN | = 2(6 +) = 16.90 cm

a = b = 16 cm, c = 28 cm

| ∠ ACD | = 27°

α = 108°, β = 54°, γ = 18°

a = 15 cm, b = 22 cm, c = 17 cm, α = 42°54', β = 86°38', γ = 50°29'

α = 45°, β = 60°, γ = 75°, b = = 1.73, c = 1.93

h = 325.17 m

w = 14.6 m

γ = 61°03', a = 30.28, b = 35.87, c = 33.94

P = 3 + = 4.73, A = = 0.87

a = 18.41 cm, b = 14.86 cm, c = 6.51 cm

b = 15.28, c = 10.70, α = 31°58', γ = 42°27'

A = 3.85

yes, γ = 91°18' > 90°

a = 20.86, b = 55.30, c = 68.05, γ = 119°32'

105.16 N

d₁ = 12.54 cm, d₂ = 7.14 cm

a = = 14.2, b = = 9.67, c = = 17.18

The triangle is right-angled.

r = 3

r = 17 cm

a = 13, h = = 9.23, e = 10, f = 24

b = = 3.75, c = = 6.25

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